8.Mechanical Properties of Solids
hard

Two blocks of masses $m$ and $M$ are connected by means of a metal wire of cross-sectional area $A$ passing over a frictionless fixed pulley as shown in the figure. The system is then released. If $M = 2\, m$, then the stress produced in the wire is

A

$\frac{{2mg}}{{3A}}$

B

$\frac{{4mg}}{{3A}}$

C

$\frac{{mg}}{{A}}$

D

$\frac{{3mg}}{{4A}}$

(JEE MAIN-2013)

Solution

Tension in the wire, $T = \left( {\frac{{2mM}}{{m + M}}} \right)g.$

$Stress = \frac{{Force/Tension}}{{Area}} = \frac{{2mM}}{{A\left( {m + M} \right)}}g$

$ = \frac{{2\left( {m \times 2m} \right)g}}{{A\left( {m + 2m} \right)}}\left( {M = 2m\,given} \right)$

$ = \frac{{4{m^2}}}{{3mA}}g = \frac{{4mg}}{{3A}}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.