A wire of length L and radius r is rigidly fi | vedclass

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Question

(a) $l = \frac{{FL}}{{AY}} = \frac{{FL}}{{\pi {r^2}Y}}	herefore l \propto \frac{{FL}}{{{r^2}}}$ ($Y =$ constant)

$\frac{{{l_2}}}{{{l_1}}} = \frac{

Vedclass · Accepted Answer

$l$

Vedclass · Answer

(a) $l = \frac{{FL}}{{AY}} = \frac{{FL}}{{\pi {r^2}Y}}	herefore l \propto \frac{{FL}}{{{r^2}}}$ ($Y =$ constant)

$\frac{{{l_2}}}{{{l_1}}} = \frac{{{F_2}}}{{{F_1}}} 	imes \frac{{{L_2}}}{{{L_1}}}{\left( {\frac{{{r_1}}}{{{r_2}}}} ight)^2} = 2 	imes 2 	imes {\left( {\frac{1}{2}} ight)^2} = 1$

 ${l_2} = {l_1}$ i.e. increment in its length will be $l.$

A wire of length $L$ and radius $r$ is rigidly fixed at one end. On stretching the other end of the wire with a force $F$, the increase in its length is $l$. If another wire of same material but of length $2L$ and radius $2r$ is stretched with a force of $2F$, the increase in its length will be

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