Two bodies A (of mass 1,kg ) and B (of mass 3,kg ) are dropped from heights of 16,m and 25,m respect

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2.Motion in Straight Line

medium

Two bodies $A$ (of mass $1\,kg$) and $B$ (of mass $3\,kg$) are dropped from heights of $16\,m$ and $25\,m$ respectively . The ratio of the time taken by them to reach the ground is

$0.8$

$1.25$

$2.4$

$0.42$

(AIPMT-2006)

Solution

$\begin{array}{l}
Time\,taken\,by\,a\,body\,fall\,form\,a\,hight\,h\,\\
to\,reach\,the\,ground\,is\,t = \sqrt {\frac{{2h}}{g}.} \\
\therefore \,\frac{{{t_A}}}{{{t_s}}} = \frac{{\sqrt {\frac{{2{h_A}}}{g}} }}{{\sqrt {\frac{{2{h_g}}}{g}} }} = \sqrt {\frac{{{h_A}}}{{{h_B}}}} = \sqrt {\frac{{16}}{{25}}} = \frac{4}{5}.
\end{array}$

Standard 11

Physics

A particle is projected up with an initial velocity of $80\;ft/\sec $. The ball will be at a height of $96\;ft$ from the ground after

medium

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hard

(JEE MAIN-2022)

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hard

(KVPY-2016)

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medium

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easy

Two bodies $A$ (of mass $1\,kg$) and $B$ (of mass $3\,kg$) are dropped from heights of $16\,m$ and $25\,m$ respectively . The ratio of the time taken by them to reach the ground is

Solution

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