Gujarati
14.Probability
easy

Two cards are drawn from a pack of $52$ cards. What is the probability that at least one of the cards drawn is an ace

A

$\frac{{33}}{{221}}$

B

$\frac{{188}}{{221}}$

C

$\frac{1}{{26}}$

D

$\frac{{21}}{{221}}$

Solution

(a) Required probability is $1 – P$ (no ace)

$ = 1 – \frac{{48}}{{52}}.\frac{{47}}{{51}}$

$ = \frac{{663 – 564}}{{13\,.\,51}} = \frac{{99}}{{13\,.\,51}} = \frac{{33}}{{221}}.$

Standard 11
Mathematics

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