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14.Probability
easy
Two cards are drawn from a pack of $52$ cards. What is the probability that at least one of the cards drawn is an ace
A
$\frac{{33}}{{221}}$
B
$\frac{{188}}{{221}}$
C
$\frac{1}{{26}}$
D
$\frac{{21}}{{221}}$
Solution
(a) Required probability is $1 – P$ (no ace)
$ = 1 – \frac{{48}}{{52}}.\frac{{47}}{{51}}$
$ = \frac{{663 – 564}}{{13\,.\,51}} = \frac{{99}}{{13\,.\,51}} = \frac{{33}}{{221}}.$
Standard 11
Mathematics