Two dice are thrown simultaneously. probability of obtaining a multiple of 2 on one of them and a mu

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14.Probability

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Two dice are thrown simultaneously. What is the probability of obtaining a multiple of $2$ on one of them and a multiple of $3$ on the other

A

$\frac{5}{{36}}$

B

$\frac{{11}}{{36}}$

C

$\frac{1}{6}$

D

$\frac{1}{3}$

Solution

(b) Favourable cases for one are three i.e. $2, 4$ and $6$ and for other are two $i.e.$ $3, 6$.

Hence required probability $ = \left[ {\left( {\frac{{3 \times 2}}{{36}}} \right){\rm{ }}2 – \frac{1}{{36}}} \right] = \frac{{11}}{{36}}$

{As same way happen when dice changes numbers among themselves}

Standard 11

Mathematics

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