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14.Probability
easy
In a single throw of two dice, the probability of getting more than $7$ is
A
$\frac{7}{{36}}$
B
$\frac{7}{{12}}$
C
$\frac{5}{{12}}$
D
$\frac{5}{{36}}$
Solution
(c) Required probability is
$P(8) + P(9) + P(10) + P(11) + P(12)$
$ = \frac{5}{{36}} + \frac{4}{{36}} + \frac{3}{{36}} + \frac{2}{{36}} + \frac{1}{{36}} = \frac{{15}}{{36}} = \frac{5}{{12}}$.
Standard 11
Mathematics
