Two dice are thrown simultaneously. probability of obtaining sum of numbers less than 11

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14.Probability

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Two dice are thrown simultaneously. What is the probability of obtaining sum of the numbers less than $11$

A

$\frac{{17}}{{18}}$

B

$\frac{1}{{12}}$

C

$\frac{{11}}{{12}}$

D

None of these

Solution

(c) Favourable cases to get the sum not less than $11$ are $\{ (5,\,\,6),\,(6,\,\,6),\,(6,\,\,5)\} = 3$

Hence favourable cases to get the sum less than $11$ are $(36 – 3) = 33$.

So required probability $ = \frac{{33}}{{36}} = \frac{{11}}{{12}}.$

Standard 11

Mathematics

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