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2. Electric Potential and Capacitance
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Two dielectric slab of dielectric constant $K_1$ and $K_2$ and of same thickness is inserted in parallel plats capacitor and $K_1 = 2K_2$ . Potential difference across slabs are $V_1$ and $V_2$ respectively then

A
$V_1 = V_2$
B
$V_1 = 2V_2$
C
$2V_1 = V_2$
D
$4V_1 = V_2$
Solution
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Standard 12
Physics
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