A parallel-plate capacitor of area $A,$ plate separation $d$ and capacitance $C$ is filled with four dielectric materials having dielectric constants $K_1,K_2,K_3$ and $K_4$ as shown in the figure. If a single dielectric material is to be used to have the same capacitance $C$ in this capacitor, then its dielectric constant $K$ is given by
$\frac{2}{K} = \frac{3}{{{K_1} + {K_2} + {K_3}}} + \frac{1}{{{K_4}}}\;\;\;\;$
$\;\frac{1}{K} = \frac{1}{{{K_1}}} + \frac{1}{{{K_2}}} + \frac{1}{{{K_3}}} + \frac{3}{{2{K_4}}}$
$K=K_1+K_2+K_3+3K_4$
$K=$ $\frac{2}{3}\left[ {{K_1} + {K_2} + {K_3}} \right] + 2{K_4}$
A parallel plate capacitor is connected to a battery and a dielectric slab is inserted between the plates, then which quantity increase
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