Work of $3.0\times10^{-4}$ joule is required to be done in increasing the size of a soap film from $10\, cm\times6\, cm$ to $10\, cm\times11\, cm$. The surface tension of the film is

  • A

    $5\times10^{-2}\, N/m$

  • B

    $3\times10^{-2}\, N/m$

  • C

    $1.5\times10^{-2}\, N/m$

  • D

    $1.2\times10^{-2}\, N/m$

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