A spherical drop of water has 1, mm radius. If surface tension of water is 70×10^{-3}, N/m . Then d

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9-1.Fluid Mechanics

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A spherical drop of water has $1\, mm$ radius. If the surface tension of water is $70\times10^{-3}\, N/m$ . Then the difference of pressures between inside and outside of the spherical drop is :

A

$140\, N /m^2$

B

$40\, N/m$

C

$35\, Nm^2$

D

none of these

Solution

Excess pressure, $\Delta \mathrm{p}=\frac{2 \mathrm{T}}{\mathrm{r}}$

$=\frac{2 \times 70 \times 10^{-3}}{1 \times 10^{-3}}=140$ $\mathrm{newton}$ $/ \mathrm{m}^{2}$

Standard 11

Physics

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