Two forces acting on point $A$ along their side and having magnitude reciprocal to length of side then resultant of these forces will be proportional to
$\frac {1}{BC}$
$\frac {1}{AD}$
$\frac {1}{BD}$
$\frac {1}{CD}$
The vectors $\vec{A}$ and $\vec{B}$ are such that
$|\vec{A}+\vec{B}|=|\vec{A}-\vec{B}|$
The angle between the two vectors is
A particle has displacement of $12 \,m$ towards east and $5 \,m$ towards north then $6 \,m $ vertically upward. The sum of these displacements is........$m$
Two forces $3\,N$ and $2\, N$ are at an angle $\theta$ such that the resultant is $R$. The first force is now increased to $ 6\,N$ and the resultant become $2R$. The value of is ....... $^o$
When $n$ vectors of different magnitudes are added, we get a null vector. Then the value of $n$ cannot be