The angle between vector (overrightarrow{{A}} | vedclass

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Question

Angle between $\overrightarrow{{A}}$ and $\overrightarrow{{B}}, 	heta=60^{\circ}$

Angle betwenn $\overrightarrow{{A}}$ and $\overrightarrow{{A}}-\

Vedclass · Accepted Answer

$	an ^{-1}\left(\frac{\sqrt{3} {B}}{2 {A}-{B}}ight)$

Vedclass · Answer

Angle between $\overrightarrow{{A}}$ and $\overrightarrow{{B}}, 	heta=60^{\circ}$

Angle betwenn $\overrightarrow{{A}}$ and $\overrightarrow{{A}}-\overrightarrow{{B}}$

$	an \alpha=\frac{B \sin 	heta}{A-B \cos 	heta}$

$=\frac{B \sqrt{\frac{3}{2}}}{A-B 	imes \frac{1}{2} 2}$

$	an \alpha=\frac{\sqrt{3} B}{2 A-B}$

The angle between vector $(\overrightarrow{{A}})$ and $(\overrightarrow{{A}}-\overrightarrow{{B}})$ is :

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