The angle between vector $(\overrightarrow{{A}})$ and $(\overrightarrow{{A}}-\overrightarrow{{B}})$ is :
$\tan ^{-1}\left(\frac{-\frac{{B}}{2}}{{A}-{B} \frac{\sqrt{3}}{2}}\right)$
$\tan ^{-1}\left(\frac{{A}}{0.7 {B}}\right)$
$\tan ^{-1}\left(\frac{\sqrt{3} {B}}{2 {A}-{B}}\right)$
$\tan ^{-1}\left(\frac{{B} \cos \theta}{{A}-{B} \sin \theta}\right)$
Two forces of magnitude $8 \,N$ and $15 \,N$ respectively act at a point. If the resultant force is $17 \,N$, the angle between the forces has to be .......
If $\overrightarrow R$ is the resultant vector of two vectors $\overrightarrow A $ and $\overrightarrow B $, then $\overrightarrow {\left| R \right|} \,...\,\overrightarrow {\left| A \right|} \, + \,\overrightarrow {\left| B \right|} $.