Two forces of 10 ,N and 6 ,N act upon a body. direction of forces are unknown. resultant force on bo

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3-1.Vectors

easy

Two forces of $10 \,N$ and $6 \,N$ act upon a body. The direction of the forces are unknown. The resultant force on the body may be .........$N$

$15$

$3$

$17$

$2$

Solution

(a)

The resultant of two vectors always lie between $(A+B)$ and $(A-B)$. So the resultant of $10 \,N$ and $6 \,N$ should lie between $16 \,N$ and $4 \,N$.

So answer is $15 \,N$.

Standard 11

Physics

Two forces with equal magnitudes $F$ act on a body and the magnitude of the resultant force is $F/3$. The angle between the two forces is

medium

Two forces of magnitude $8 \,N$ and $15 \,N$ respectively act at a point. If the resultant force is $17 \,N$, the angle between the forces has to be …….

easy

Two vectors $\vec A$ and $\vec B$ have equal magnitudes. The magnitude of $(\vec A + \vec B)$ is $‘n’$ times the magnitude of $(\vec A – \vec B)$. The angle between $ \vec A$ and $\vec B$ is

hard

(JEE MAIN-2021)

“Explain Triangle method (head to tail method) of vector addition.”