Two given circles {x^2} + {y^2} + ax + by + c = 0 and {x^2} + {y^2} + dx + ey + f = 0 will intersect

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10-1.Circle and System of Circles

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Two given circles ${x^2} + {y^2} + ax + by + c = 0$ and ${x^2} + {y^2} + dx + ey + f = 0$ will intersect each other orthogonally, only when

A

$a + b + c = d + e + f$

B

$ad + be = c + f$

C

$ad + be = 2c + 2f$

D

$2ad + 2be = c + f$

Solution

(c) From Condition for orthogonal intersection, $\frac{{ad}}{2} + \frac{{be}}{2} = c + f$

Standard 11

Mathematics

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