Two given circles ${x^2} + {y^2} + ax + by + c = 0$ and ${x^2} + {y^2} + dx + ey + f = 0$ will intersect each other orthogonally, only when

  • A

    $a + b + c = d + e + f$

  • B

    $ad + be = c + f$

  • C

    $ad + be = 2c + 2f$

  • D

    $2ad + 2be = c + f$

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