Gujarati
Hindi
4-1.Newton's Laws of Motion
hard

Two masses $m$ and $M$ are attached to the strings as shown in the figure. If the system is in equilibrium, then

A

$\cot \theta=1+\frac{2 m}{M}$

B

$\tan \theta=1+\frac{2 M}{m}$

C

$\tan \theta=1+\frac{2 m}{M}$

D

$\cot \theta=1+\frac{2 M }{ m }$

Solution

$\frac{2 T}{\sqrt{2}}=m g$

$T=\frac{m g}{\sqrt{2}}$

$T^{\prime} \cos \theta=\frac{T}{\sqrt{2}}$

$T^{\prime} \sin \theta=\frac{T}{\sqrt{2}}+M g$

$\frac{T}{\sqrt{2}}(\tan \theta-1)=M g$

$\tan \theta=1+\frac{2 M}{m}$

Standard 11
Physics

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