Two masses ${m_A}$and ${m_B}$moving with velocities ${v_A}$and ${v_B}$in opposite directions collide elastically. After that the masses ${m_A}$and ${m_B}$move with velocity ${v_B}$and ${v_A}$respectively. The ratio $ \frac{m_A}{m_B} =$
Two masses ${m_A}$and ${m_B}$moving with velocities ${v_A}$and ${v_B}$in opposite directions collide elastically. After that the masses ${m_A}$and ${m_B}$move with velocity ${v_B}$and ${v_A}$respectively. The ratio $ \frac{m_A}{m_B} =$
- A
$1$
- B
$\frac{{{v_A} - {v_B}}}{{{v_A} + {v_B}}}$
- C
$({m_A} + {m_B})/{m_A}$
- D
${v_A}/{v_B}$
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$(i)$ The sphere $A$ comes to rest after collision.
$(ii)$ The sphere $B$ will move with a speed of $8\ m/s$ after collision.
$(iii)$ The directions of motion $A$ and $B$ after collision are at right angles.
$(iv)$ The speed of $B$ after collision is $4\ m/s$ . The correct option is
A smooth sphere $A$ of mass $m$ collides elastically with an identical sphere $B$ at rest. The velocity of $A$ before collision is $8\ m/s$ in a direction making $60^o$ with the line of centres at the time of impact.
$(i)$ The sphere $A$ comes to rest after collision.
$(ii)$ The sphere $B$ will move with a speed of $8\ m/s$ after collision.
$(iii)$ The directions of motion $A$ and $B$ after collision are at right angles.
$(iv)$ The speed of $B$ after collision is $4\ m/s$ . The correct option is