Two masses m and M are attached to the string | vedclass

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Question

$m g=2 T \sin 45^{\circ}$

$m g=\sqrt{2 T}$

$T_{1} \cos 	heta=T \cos 45^{\circ}$

$T_{1} \cos 	heta=\frac{T}{\sqrt{2}}=\frac{m g}{2}$

$\le

Vedclass · Accepted Answer

$tan	heta = 1 +\frac{{2M}}{m}$

Vedclass · Answer

$m g=2 T \sin 45^{\circ}$

$m g=\sqrt{2 T}$

$T_{1} \cos 	heta=T \cos 45^{\circ}$

$T_{1} \cos 	heta=\frac{T}{\sqrt{2}}=\frac{m g}{2}$

$\left\{T=\frac{m g}{\sqrt{2}}ight\}$

Further, $M g+T \cos 45^{\circ}=T_{1} \sin 	heta$

$T_{1} \sin 	heta=M g+\frac{M g}{\sqrt{2}} \frac{1}{\sqrt{2}}$

$T_{1} \sin 	heta=M g+\frac{m g}{2}$

$	an 	heta=\frac{M g+\frac{m g}{2}}{\frac{M g}{2}}=1+\frac{2M}{m}$

Two masses $m$ and $M$ are attached to the strings as shown in the figure. If the system is in equilibrium, then

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