Two masses of 1,kg and 2,kg respectively are connected by a massless spring as sh

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4-1.Newton's Laws of Motion

medium

Two masses of $1\,kg$ and $2\,kg$ respectively are connected by a massless spring as shown in figure. A force of $20\,N$ acts on the $2\,kg$ mass at the instant when the $1\, kg$ mass has an acceleration of $10\,ms^{-2}$ towards right, the acceleration of the $2\,\,kg$ mass is ......... $ms^{-2}$

A$2$

B$5$

C$10$

D$20$

Solution

$\mathrm{F}=\mathrm{m}_{1} \mathrm{a}_{1}+\mathrm{m}_{2} \mathrm{a}_{2}$
[Newton's law for system]
$20=1 \times 10+2 \times a$
$a=5 \mathrm{m} / \mathrm{s}^{2}$

Standard 11

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medium

Two masses of $1\,kg$ and $2\,kg$ respectively are connected by a massless spring as shown in figure. A force of $20\,N$ acts on the $2\,kg$ mass at the instant when the $1\, kg$ mass has an acceleration of $10\,ms^{-2}$ towards right, the acceleration of the $2\,\,kg$ mass is ......... $ms^{-2}$

Solution

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When acceleration of $5\ kg$ block is $2\ m/s^2$ as shown in figure, then what will be the acceleration of $15\ kg$ block ………… $m/s^2$

A body of mass $m$ is tied to one end of a spring and whirled round in a horizontal plane with a constant angular velocity. The elongation in the spring is $1\, cm$. If the angular velocity is doubled, the elongation in the spring is $5\, cm$. The original length of the spring is ……… $cm$

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