Two masses of 10,kg and 20,kg respectively are connected by a massless spring as shown in figure. A

English

Gujarati

Hindi

4-1.Newton's Laws of Motion

normal

Two masses of $10\,kg$ and $20\,kg$ respectively are connected by a massless spring as shown in figure. A force of $200\,N$ acts on the $20\,kg$ mass at the instant when the $10\,kg$ mass has an acceleration of $12\,ms ^{-2}$ towards right, the aceleration of the $20\,kg$ mass is:

A

$4\,ms ^{-2}$

B

$2\,ms ^{-2}$

C

$10\,ms ^{-2}$

D

$20\,ms ^{-2}$

Solution

Force on $10\,kg$ block $=12 \times 10=120\,N$ So,

$a=\frac{80}{20}=4\,m / s ^2$

Standard 11

Physics

Share

Similar Questions

A particle of mass $\mathrm{m}$ is fixed to one end of a light spring having force constant $\mathrm{k}$ and unstretched length $\ell .$ The other end is fixed. The system is given an angular speed $\omega$ about the fixed end of the spring such that it rotates in a circle in gravity free space. Then the stretch in the spring is

normal

A balloon with mass $'m'$ is descending down with an acceleration $'a'$ (where $a < g$ ). How much mass should be removed from it so that it starts moving up with an acceleration $'a'$ ?

normal

A block of mass $1 kg$ is suspended by a string of mass $1 kg$, length $1 m$ as shown in figure. $(g=10\,m /$ $s ^2$ ) Calculate:Force exerted by support on string.

normal

A cricketer catches a ball of mass $150\; gm$ in $0.1$ second moving with speed $20\, m/s$. Then he experiences force of ….. $N$

normal

A road is $10\, m$ wide. Its radius of curvature is $50\, m$. The outer edge is above the lower edge by a distance of $1.5\, m$. this road is most suited for the velocity …….. $m/s$

normal