Two moles of an ideal monoatomic gas at {27^o | vedclass

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Question

(b) $W = \frac{{\mu R({T_1} - {T_2})}}{{(\gamma - 1)}} = \frac{{\mu R{T_1}}}{{(\gamma - 1)}}\left[ {1 - \frac{{{T_2}}}{{{T_1}}}} \right]$
$ = \frac{{

Vedclass · Accepted Answer

$2767.23$

Vedclass · Answer

(b) $W = \frac{{\mu R({T_1} - {T_2})}}{{(\gamma - 1)}} = \frac{{\mu R{T_1}}}{{(\gamma - 1)}}\left[ {1 - \frac{{{T_2}}}{{{T_1}}}} ight]$
$ = \frac{{\mu R{T_1}}}{{(\gamma - 1)}}\left[ {1 - {{\left( {\frac{{{V_1}}}{{{V_2}}}} ight)}^{\gamma - 1}}} ight]$
$ = \frac{{2 	imes 8.31 	imes 300}}{{\left( {\frac{5}{3} - 1} ight)}}\left[ {1 - {{\left( {\frac{1}{2}} ight)}^{\frac{5}{3} - 1}}} ight]$$ = + 2767.23\;J$

Two moles of an ideal monoatomic gas at ${27^o}C$ occupies a volume of $V.$ If the gas is expanded adiabatically to the volume $2V,$ then the work done by the gas will be ....... $J$ $[\gamma = 5/3,\,R = 8.31J/mol\,K]$

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