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3-2.Motion in Plane
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Two objects are thrown up at angles of $45^{\circ}$ and $60^{\circ}$ respectively, with the horizontal. If both objects attain same vertical height, then the ratio of magnitude of velocities with which these are projected is .........
A
$\sqrt{\frac{5}{3}}$
B
$\sqrt{\frac{3}{5}}$
C
$\sqrt{\frac{2}{3}}$
D
$\sqrt{\frac{3}{2}}$
Solution
(d)
$h_1=h_2$
$\frac{u_1^2 \sin ^2 45^{\circ}}{2 g}=\frac{V_2^2 \sin ^2 60^{\circ}}{2 g}$
$\frac{u_1^2}{V_2^2}=\frac{\frac{\sqrt{3}}{2} \times \frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{3}{2}$
$\frac{V_1}{V_2}=\sqrt{\frac{3}{2}}$
Standard 11
Physics