3-2.Motion in Plane
medium

Two objects are thrown up at angles of $45^{\circ}$ and $60^{\circ}$ respectively, with the horizontal. If both objects attain same vertical height, then the ratio of magnitude of velocities with which these are projected is .........

A

$\sqrt{\frac{5}{3}}$

B

$\sqrt{\frac{3}{5}}$

C

$\sqrt{\frac{2}{3}}$

D

$\sqrt{\frac{3}{2}}$

Solution

(d)

$h_1=h_2$

$\frac{u_1^2 \sin ^2 45^{\circ}}{2 g}=\frac{V_2^2 \sin ^2 60^{\circ}}{2 g}$

$\frac{u_1^2}{V_2^2}=\frac{\frac{\sqrt{3}}{2} \times \frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{3}{2}$

$\frac{V_1}{V_2}=\sqrt{\frac{3}{2}}$

Standard 11
Physics

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