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14.Waves and Sound
easy
Two perfectly identical wires are in unison. When the tension in one wire is increased by $1\%$, then on sounding them together $3$ beats are heard in $2 \,sec$. The initial frequency of each wire is .... ${\sec ^{ - 1}}$
A
$220$
B
$320$
C
$150$
D
$300$
Solution
(d) Initial frequency of each wire $(n)$
$ = \frac{{{\rm{(Number}}\;{\rm{of}}\;{\rm{beats}}\;{\rm{heared}}\;{\rm{per}}\;{\rm{sec)}} \times {\rm{200}}}}{{{\rm{(per}}\;{\rm{centage}}\;{\rm{change}}\;{\rm{in}}\;{\rm{tension}}\;{\rm{of}}\;{\rm{the}}\;{\rm{wire)}}}}$
$ = \frac{{(3/2) \times 200}}{1} = 300{\sec ^{ – 1}}$
Standard 11
Physics