1. Electric Charges and Fields
hard

બે બિંદુવત વિજભારો  $q_1\,(\sqrt {10}\,\,\mu C)$ અને $q_2\,(-25\,\,\mu C)$ ને $x -$ અક્ષ પર અનુક્રમે $x=1 \,m$ અને $x=4\ m$ પર મુકેલ છે. $y- $અક્ષ પરના $y=3\,m$ પર વિદ્યુત ક્ષેત્રનું મૂલ્ય ($V/m$ માં) ______ હશે. 

A

$(63\hat i - 27\hat j) \times {10^2}$

B

$(-63\hat i + 27\hat j) \times {10^2}$

C

$(81\hat i - 81\hat j) \times {10^2}$

D

$(-81\hat i + 81\hat j) \times {10^2}$

(JEE MAIN-2019)

Solution

$\overrightarrow {\text{E}}  = \frac{{{\text{k}}{{\text{q}}_1}}}{{{\text{r}}_1^3}}{\overrightarrow {\text{r}} _1} + \frac{{{\text{k}}{q_2}}}{{{\text{r}}_2^3}}{\overrightarrow {\text{r}} _2}$

$ = {\text{k}} \times {10^{ – 6}}\left[ {\frac{{\sqrt {10} }}{{10\sqrt {10} }}( – \widehat {\text{i}} + 3\widehat {\text{j}}) + \frac{{( – 25)}}{{125}}( – 4\widehat {\text{i}} + 3\widehat {\text{j}})} \right]$

$ = \left( {9 \times {{10}^3}} \right)\left[ {\frac{1}{{10}}( – \widehat {\text{i}} + 3\widehat {\text{j}}) – \frac{1}{5}( – 4\widehat {\text{i}} + 3\widehat {\text{j}})} \right]$

$ = \left( {9 \times {{10}^3}} \right)\left[ {\left( { – \frac{1}{{10}} + \frac{4}{5}} \right)\widehat {\text{i}} + \left( {\frac{3}{{10}} – \frac{3}{5}} \right)\widehat {\text{i}}} \right]$

$ = 9000\left( {\frac{7}{{10}}\widehat {\text{i}} – \frac{3}{{10}}\widehat {\text{j}}} \right)$

$ = (63\widehat {\text{i}} – 27\widehat {\text{j}})(100)$

Standard 12
Physics

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