Gujarati
Hindi
14.Waves and Sound
medium

Two points on a travelling wave having frequency $500\, Hz$ and velocity $300\, m/s$  are $60^o$ out of phase, then the minimum distance between the two points is ..... $m$

A

$0.2$

B

$0.1$

C

$0.5$

D

$0.4$

Solution

Wavelength of the wave is$:$

$\lambda=\frac{v}{f}=\frac{300}{500}=0.6 \mathrm{m}$

$360^{\circ}$ phase difference corresponds to a distance of $1$ wavelength or

$360^{\circ}$ phase difference corresponds to a distance of $0.6 \mathrm{m}$

$60^{\circ}$ phase difference corresponds to a distance of $0.6 / 6=0.1 \mathrm{m}$

Standard 11
Physics

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