Two positively charged spheres of masses m_1 | vedclass

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Question

(b)

In given situation, forces on each of charged sphere are

$(i)$ gravitational pull ( $m g)$

$(ii)$ electrostatic repulsion $\left(\frac{k

Vedclass · Accepted Answer

$m_1=m_2$

Vedclass · Answer

(b)

In given situation, forces on each of charged sphere are

$(i)$ gravitational pull ( $m g)$

$(ii)$ electrostatic repulsion $\left(\frac{k q_1 q_2}{r^2}ight)$

$(iii)$ tension of string $(T)$

as shown below.

If we resolve tension in horizontal and vertical directions, we have following situation in equilibrium.

$	ext { So, } T \sin 	heta=\frac{k q_1 q_2}{r^2} 	ext { and } T \cos 	heta=m g$

$\Rightarrow \quad 	an 	heta=\frac{k q_1 q_2}{r^2 \cdot m g}$

As angle $	heta$ is same for both spheres, we have

$	an 	heta_1=	an 	heta_2$

or $\frac{k q_1 q_2}{r^2 m_1 g}=\frac{k q_1 q_2}{r^2 m_2 g}$

$\Rightarrow m_1=m_2$

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