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Two projectiles are thrown simultaneously in the same plane from the same point. If their velocities are $v_1$ and $v_2$ at angles $\theta _1$ and $\theta_2$ respectively from the horizontal, then answer the following question
If $v_1 = v_2$ and $\theta _1 > \theta _2$, then choose the incorrect statement
The slope of the trajectory of particle $2$ with respect to $1$ is always positive
Particle $2$ moves under the particle $1$
Both the particle will have the same range if $\theta _1 > 45^o$ and $\theta _2 < 45^o$ and $\theta _1 + \theta _2 = 90^o$
none of these
Solution
$x=v \cos \theta t=50 \times \frac{3}{5} \times 2=60 \mathrm{m}$
$y=u \sin \theta t-\frac{1}{2} g t^{2}=50 \times \frac{4}{5} \times 2-\frac{1}{2} \times 10 \times 2^{2}=60 m$
$d=\sqrt{x^{2}+y^{2}}$
$=\sqrt{60^{2}+60^{2}}=60 \sqrt{2} m$
