Gujarati
10-2.Transmission of Heat
medium

Two rods having thermal conductivity in the ratio of $5 : 3$ having equal lengths and equal cross-sectional area are joined by face to face. If the temperature of the free end of the first rod is $100°C$ and free end of the second rod is $20°C$ . Then temperature of the junction is...... $^oC$

A

$70$

B

$50$

C

$80$

D

$90$

Solution

(a) Temperature of interface $\theta = \frac{{{K_1}{\theta _1} + {K_2}{\theta _2}}}{{{K_1} + {K_2}}}$
It is given that $\frac{{{K_1}}}{{{K_2}}} = \frac{5}{3}$

==> ${K_1} = 5K$ and ${K_2} = 3K$

$\theta = \frac{{5K \times 100 + 3K \times 20}}{{5K + 3K}}$$ = \frac{{560K}}{{8K}}=70°C$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.