Two springs have their force constant as k₁ and k₂ (k₁ > k₂) . when they are stretc

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5.Work, Energy, Power and Collision

medium

Two springs have their force constant as $k_1$ and $k_2 (k_1 > k_2)$. when they are stretched by the same force

A

No work is done in case of both the springs

B

Equal work is done in case of both the springs

C

More work is done in case of second spring

D

More work is done in case of first spring

Solution

$\mathrm{W}=\frac{1}{2} \mathrm{kx}^{2}=\frac{(\mathrm{kx})^{2}}{2 \mathrm{k}} \quad(\because \mathrm{F}=\mathrm{kx})$

$\mathrm{W}=\frac{\mathrm{F}^{2}}{2 \mathrm{k}}$ So $\mathrm{k} \uparrow \mathrm{W} \downarrow$ and $\mathrm{k} \downarrow, \mathrm{W} \uparrow$

or $\frac{W_{1}}{W_{2}}=\frac{k_{2}}{k_{1}} \Rightarrow$$\therefore \mathrm{k}_{2}<\mathrm{k}_{1}$$\therefore \mathrm{W}_{2}>\mathrm{W}_{1}$

Standard 11

Physics

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