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5.Work, Energy, Power and Collision
easy
Two springs have their force constant as ${k_1}$ and ${k_2}({k_1} > {k_2})$. When they are stretched by the same force
A
No work is done in case of both the springs
B
Equal work is done in case of both the springs
C
More work is done in case of second spring
D
More work is done in case of first spring
Solution
(c)$W = \frac{{{F^2}}}{{2k}}$
If both springs are stretched by same force then$W \propto \frac{1}{k}$
As ${k_1} > {k_2}$ therefore ${W_1} < {W_2}$
i.e. more work is done in case of second spring.
Standard 11
Physics
