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13.Oscillations
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Two oscillating systems; a simple pendulum and a vertical spring-mass-system have same time period of motion on the surface of the Earth. If both are taken to the moon, then-
A
Time period of the simple pendulum will be more than that of the spring-mass system.
B
Time period of the simple pendulum will be equal is that is of the spring-mass system.
C
Time period of the simple pendulum will be less than of the spring-mass system.
D
Nothing can be said definitely without observation.
Solution
(a)
For simple pendulum: $T =2 \pi \sqrt{\frac{\ell}{ g }}$ As g will decrease on moon, time period will increase
For spring mass system : $T=2 \pi \sqrt{\frac{m}{k}}$
It will not change and remains the same
Standard 11
Physics
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