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14.Probability
hard
Two squares are chosen at random on a chessboard (see figure). The probability that they have a side in common is :

A
$\frac{2}{7}$
B
$\frac{1}{18}$
C
$\frac{1}{7}$
D
$\frac{1}{9}$
(JEE MAIN-2021)
Solution
Total ways of choosing square $={ }^{64} \mathrm{C}_{2}$
$=\frac{64 \times 63}{2 \times 1}=32 \times 63$
ways of choosing two squares having common side $=2(7 \times 8)=112$
Required probability $=\frac{112}{32 \times 63}=\frac{16}{32 \times 9}=\frac{1}{18}$.
Standard 11
Mathematics