Two stars of masses m_1 and m_2 are parts of | vedclass

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Question

The situation is as shown in the figure.

According to Newton's law of gravitation.

gravitational force between two bodies of

masses $\mathrm{m}

Vedclass · Accepted Answer

$\frac{{{m_1}{m_2}G}}{{{{({r_1} + {r_2})}^2}}}$

Vedclass · Answer

The situation is as shown in the figure.

According to Newton's law of gravitation.

gravitational force between two bodies of

masses $\mathrm{m}_{1}$ and $\mathrm{m}_{2}$ is.

$F=\frac{\mathrm{Gm}_{1} \mathrm{m}_{2}}{\mathrm{r}^{2}}$

where $\mathrm{r}$ is the distance between the two masses.

Here, $\mathrm{r}=\mathrm{r}_{1}+\mathrm{r}_{2}$

$	herefore \quad \mathrm{F}=\frac{\mathrm{Gm}_{1} \mathrm{m}_{2}}{\left(\mathrm{r}_{1}+\mathrm{r}_{2}ight)^{2}}$

Two stars of masses $m_1$ and $m_2$ are parts of a binary star system. The radii of their orbits are $r_1$ and $r_2$ respectively, measured from the centre of mass of the system. The magnitude of gravitational force $m_1$ exerts on $m_2$ is