Two stones are thrown with same speed u at di | vedclass

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Question

(b)
If range is same then, one angle is $	heta$ and other angle is $(90-	heta)$
$\Rightarrow h_1=\frac{u^2 \sin ^2 	heta}{2 g}, h_2=\frac{u^2 \si

Vedclass · Accepted Answer

$\frac{u^2}{2 g}$

Vedclass · Answer

(b)
If range is same then, one angle is $	heta$ and other angle is $(90-	heta)$
$\Rightarrow h_1=\frac{u^2 \sin ^2 	heta}{2 g}, h_2=\frac{u^2 \sin ^2(90-	heta)}{2 g}$
$h_1=\frac{u^2 \sin ^2 	heta}{2 g}, h_2=\frac{u^2 \cos ^2 	heta}{2 g}$
So, $h_1+h_2 \Rightarrow \frac{u^2 \sin ^2 	heta}{2 g}+\frac{u^2 \cos ^2 	heta}{2 g}=\frac{u^2}{2 g}\left(\sin ^2 	heta+\cos ^2 	hetaight)$
$h_1+h_2=\frac{u^2}{2 g}$

Two stones are thrown with same speed $u$ at different angles from ground in air. If both stones have same range and height attained by them are $h_1$ and $h_2$, then $h_1+h_2$ is equal to .......

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