4.Moving Charges and Magnetism
medium

Two toroids $1$ and $2$ have total number of tums $200$ and $100 $ respectively with average radii $40\; \mathrm{cm}$ and $20 \;\mathrm{cm}$ respectively. If they carry same current $i,$ the ratio of the magnetic flelds along the two loops is

A

$1:1$

B

$4:1$

C

$2:1$

D

$1:2$

(NEET-2019)

Solution

$\mathrm{B}=\frac{\mu_{0} \mathrm{N}_{\mathrm{i}}}{2 \pi \mathrm{r}}$

$\frac{\mathrm{B}_{1}}{\mathrm{B}_{2}}=\frac{\mathrm{N}_{1}}{\mathrm{N}_{2}} \frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}=\left(\frac{200}{100}\right)\left(\frac{20}{40}\right)=1: 1$

Standard 12
Physics

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