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4.Moving Charges and Magnetism
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Two very long, straight, parallel wires carry steady currents $I$ and $-I$ respectively. The distance etween the wires is $d$. At a certain instant of time, a point charge $q$ is at a point equidistant from the two wires, in the plane of the wires. Its instantaneous velocity $v$ is perpendicular to the plane of wires. The magnitude of the force due to the magnetic field acting on the charge at this instant is
A
$\frac{{{\mu _0}Iqv}}{{2\pi d}}$
B
$\frac{{2{\mu _0}Iqv}}{{\pi d}}$
C
$\frac{{{\mu _0}Iqv}}{{\pi d}}$
D
$0$
Solution
Both $v$ and $B$ are perpendicular to plane of parallel wires
$F = q(v × B) =$ zero
Standard 12
Physics
