Two waves of sound having intensities I and 4I interfere to produce interference pattern. phase diff

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14.Waves and Sound

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Two waves of sound having intensities $I$ and $4I$ interfere to produce interference pattern. The phase difference between the waves is $\pi /2$ at point $A$ and $\pi$ at point $B$. Then the difference between the resultant intensities at $A$ and $B$ is

A

$2I$

B

$4I$

C

$5I$

D

$7I$

Solution

$I(\phi)=I_{1}+I_{2}+2 \sqrt{I_{1} I_{2}} \cos \phi \ldots .(1)$

Here, $I_{1}=I$ and $I_{2}=4 I$ At point $A, \phi=\frac{\pi}{2}$

$I_{A}=I+4 I=5 I,$ At point $B, \phi=\pi$

$I_{B}=1+4 I-4 I=I, I_{A}-I_{B},=4 I$

Standard 11

Physics

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