8.Mechanical Properties of Solids
easy

Two wires $A$ and $B$ of same material have radii in the ratio $2: 1$ and lengths in the ratio $4: 1$. The ratio of the normal forces required to produce the same change in the lengths of these two wires is .......

A

$1: 1$

B

$2: 1$

C

$1: 2$

D

$1: 4$

Solution

(a)

From $\frac{F L}{A Y}=\Delta x$ $\{\because \Delta x, Y$ same $\}$

We using $F \propto \frac{L}{A} \propto \frac{L}{r^2}$

So $\frac{F_1}{F_2}=\frac{L_1}{r_1^2} \times \frac{r_2^2}{L_2}=\left(\frac{L_1}{L_2}\right) \times\left(\frac{r_2}{r_1}\right)^2$

Substitute the ratio's

We get $\frac{F_1}{F_2}=\frac{1}{1} \quad$ or $F_1: F_2:: 1: 1$

Standard 11
Physics

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