Unit vector perpendicular to vector $A =-3 \hat{ i }-2 \hat{ j }-3 \hat{ k }$ and $B =2 \hat{ i }+4 \hat{ j }+6 \hat{ k }$ both is
- A$\frac{3 \hat{ j }-2 \hat{ k }}{\sqrt{13}}$
- B$\frac{3 \hat{ k }-2 \hat{ j }}{\sqrt{13}}$
- C$\frac{-\hat{ j }+2 \hat{ k }}{\sqrt{13}}$
- D$\frac{\hat{ i }+3 \hat{ j }-\hat{ k }}{\sqrt{13}}$
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- [AIIMS 1996]