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3-1.Vectors
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Unit vector perpendicular to vector $A =-3 \hat{ i }-2 \hat{ j }-3 \hat{ k }$ and $B =2 \hat{ i }+4 \hat{ j }+6 \hat{ k }$ both is
A$\frac{3 \hat{ j }-2 \hat{ k }}{\sqrt{13}}$
B$\frac{3 \hat{ k }-2 \hat{ j }}{\sqrt{13}}$
C$\frac{-\hat{ j }+2 \hat{ k }}{\sqrt{13}}$
D$\frac{\hat{ i }+3 \hat{ j }-\hat{ k }}{\sqrt{13}}$
Solution
(a)
$\hat{ n }=\frac{ A \times B }{| A \times B |}$
$\hat{ n }=\frac{ A \times B }{| A \times B |}$
Standard 11
Physics