Variation of electrostatic potential along x- | vedclass

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Question

Electric field $E_{x}=-\frac{d V}{d x} .$ So for negative slope, field will be directed along positive $x$. Thus $x$ component at point $A$ is towards

Vedclass · Accepted Answer

$x $ component at point $C$ is along positive $x$ -axis

Vedclass · Answer

Electric field $E_{x}=-\frac{d V}{d x} .$ So for negative slope, field will be directed along positive $x$. Thus $x$ component at point $A$ is towards negative $x$ $-axis$ and $x$ component at point $C$ is along positive $x$ $-axis$ and at point $B, x$ $-component$ of field will be minimum.

Variation of electrostatic potential along $x$-direction is shown in the graph. The correct statement about electric field is

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