Water drop whose radius is $0.0015\, mm$ is falling through the air. If the coefficient of viscosity of air is $1.8 \times 10^{-5}\, kg/m-s$, then assuming buoyancy force as negligible the terminal velocity of the dorp will be
Water drop whose radius is $0.0015\, mm$ is falling through the air. If the coefficient of viscosity of air is $1.8 \times 10^{-5}\, kg/m-s$, then assuming buoyancy force as negligible the terminal velocity of the dorp will be
- A
$2.72 \times {10^{ - 4}}\,m/s$
- B
$2.72 \times {10^{ - 3}}\,m/s$
- C
$2.72 \times {10^{ - 2}}\,m/s$
- D
$2.72 \times {10^{ - 1}}\,m/s$
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