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Question

(a)

$V_{	ext {Terminal }} \propto r^2$

If initial radius $=r$, let new radius $=R$

Then $2 	imes \frac{4}{3} \pi r^3=\frac{4}{3} \pi R^3$

Vedclass · Accepted Answer

$5 	imes(4)^{13}$

Vedclass · Answer

(a)

$V_{	ext {Terminal }} \propto r^2$

If initial radius $=r$, let new radius $=R$

Then $2 	imes \frac{4}{3} \pi r^3=\frac{4}{3} \pi R^3$

$\Rightarrow(2)^{1 / 3} r=R$

$\Rightarrow V_T \propto R^2$

$\propto(2)^{2 / 3} r^2$ (For bigger drops)

$\frac{V_{T 	ext { smaller drop }}}{V_{T 	ext { bigger drop }}}=\frac{r^2}{(2)^{2 / 3} r^2}$

$\Rightarrow \frac{5}{x}=\frac{1}{(2)^{2 / 3}}$

$\Rightarrow 5 	imes(2)^{2 / 3}=x$

$\Rightarrow 5 	imes(4)^{1 / 3} \,cm / s =x$

Two equal drops are falling through air with a steady velocity of $5 \,cm / second$. If two drops coalesce, then new terminal velocity will be ......... $cm / s$

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