What concentration of Ac^- ions will reduce H | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$[A{c^ - }] = 0.036\,M$

$\mathop {HAc}\limits_{0.4(1 - \alpha )} \overset {Ka} \longleftrightarrow \mathop {{H^ + }}\limits_{0.4\,\alpha }  +

Vedclass · Accepted Answer

$0.036\ M$

Vedclass · Answer

$[A{c^ - }] = 0.036\,M$

$\mathop {HAc}\limits_{0.4(1 - \alpha )} \overset {Ka} \longleftrightarrow \mathop {{H^ + }}\limits_{0.4\,\alpha }  + \mathop {A{c^ - }}\limits_{(b + 0.4\,\alpha )} $

$0.4 \alpha=2 	imes 10^{-4}$

$\alpha=5 	imes 10^{-4}$

$\mathrm{K}_{\mathrm{a}}=\frac{\mathrm{b} 	imes 0.4 \alpha}{0.4}=1.8 	imes 10^{-5}$

$\mathrm{b}=\frac{1.8 	imes 10^{-5}}{5 	imes 10^{-4}}=0.036$

What concentration of $Ac^-$ ions will reduce $H_3O^+$ ion to $2 × 10^{-4}\ M$ in $0.40\ M$ solution of $HAc$ ? $K_a (HAc) = 1.8 × 10^{-5}$ ?

Similar Questions

For a weak acid $HA$ with dissociation constant ${10^{ - 9}},\,\,pOH$ of its $0.1 \,M$ solution is

The ionization constant of $0.1$ $M$ weak acid is $1.74 \times {10^{ - 5}}$ at $298$ $K$ temperature. Calculate $pH$ of its $0.1$ $M$ solution.

The solution of $N{a_2}C{O_3}$ has $pH$

In $20\,\, ml \,\,0.4 \,M-HA$ solution, $80\,\, ml$ water is added. Assuming volume to be additive, the $pH$ of final solution is

$(K_a \,\,of\,\, HA = 4 \times 10^{-7} ,\, log\,2 = 0.3)$

In its $0.2\,\, M$ solution, an acid ionises to an extent of $60\%$. Its hydrogen ion concentration is.....$M$