What happens when zinc granules are treated with dilute solution of $H _{2} SO _{4},\, HCl$ and $HNO _{3^{\prime}}$ also write the chemical equations if reaction occurs.

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The reaction of $Zn$ granules with

$(a)$ Dilute $H _{2} SO _{4}$

$Zn ( s )+ H _{2} SO _{4}( aq ) \rightarrow ZnSO _{4}( aq )+ H _{2}( g )$

$(b)$ Dilute $HCl$

$Zn ( s )+2 HCl ( aq ) \rightarrow ZnCl _{2}( aq )+ H _{2}( g )$

$(c)$ Dilute $HNO_3$

Reaction with dilute $HNO _{3}$ is different as compared to other acids because nitric acid is an oxidising agent and it oxidises $H _{2}$ gas evolved to $H _{2} O$.

$4 Zn ( s )+10 HNO _{2}( aq ) \rightarrow 4 Zn \left( NO _{2}\right)_{2}( aq )+5 H _{2} O ( l )+ N _{2} O ( g )$

Similar Questions

Explain the type of reactions represented by the following equations:

$(i)$ $CuSO _{4}+2 NaOH \longrightarrow Cu ( OH )_{2}+ Na _{2} SO _{4}$

Complete the missing components/variables given as $x$ and $y$ in the following reactions

$(a)$ $Pb \left( NO _{3}\right)_{2}\,(aq)+2 KI ( aq ) \longrightarrow PbI _{2}(x)+2 KNO _{3}( y )$

$(b)$ $Cu ( s )+2 Ag NO _{3}( aq ) \longrightarrow Cu \left( NO _{3}\right)_{2}( aq )+x( s )$

You could have noted that when copper powder is heated in a china dish, the surface of copper powder becomes coated with black colour substance.

$(i)$ Why has this black coloured substance formed?

$(ii)$ What is this black substance?

$(iii)$ Write the chemical equation of the reaction that takes place.

Give differences between the displacement and double displacement reactions.

On adding a drop of barium chloride solution to an aqueous solution of sodium sulphite, white precipitate is obtained.

$(a)$ Write a balanced chemical equation of the reaction involved

$(b)$ What other name can be given to this precipitation reaction ?

$(c)$ On adding dilute hydrochloric acid to the reaction mixture, white precipitate disappears. Why ?