What happens when zinc granules are treated with dilute solution of $H _{2} SO _{4},\, HCl$ and $HNO _{3^{\prime}}$ also write the chemical equations if reaction occurs.

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The reaction of $Zn$ granules with

$(a)$ Dilute $H _{2} SO _{4}$

$Zn ( s )+ H _{2} SO _{4}( aq ) \rightarrow ZnSO _{4}( aq )+ H _{2}( g )$

$(b)$ Dilute $HCl$

$Zn ( s )+2 HCl ( aq ) \rightarrow ZnCl _{2}( aq )+ H _{2}( g )$

$(c)$ Dilute $HNO_3$

Reaction with dilute $HNO _{3}$ is different as compared to other acids because nitric acid is an oxidising agent and it oxidises $H _{2}$ gas evolved to $H _{2} O$.

$4 Zn ( s )+10 HNO _{2}( aq ) \rightarrow 4 Zn \left( NO _{2}\right)_{2}( aq )+5 H _{2} O ( l )+ N _{2} O ( g )$

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