What happens when zinc granules are treated with dilute solution of $H _{2} SO _{4},\, HCl$ and $HNO _{3^{\prime}}$ also write the chemical equations if reaction occurs.
The reaction of $Zn$ granules with
$(a)$ Dilute $H _{2} SO _{4}$
$Zn ( s )+ H _{2} SO _{4}( aq ) \rightarrow ZnSO _{4}( aq )+ H _{2}( g )$
$(b)$ Dilute $HCl$
$Zn ( s )+2 HCl ( aq ) \rightarrow ZnCl _{2}( aq )+ H _{2}( g )$
$(c)$ Dilute $HNO_3$
Reaction with dilute $HNO _{3}$ is different as compared to other acids because nitric acid is an oxidising agent and it oxidises $H _{2}$ gas evolved to $H _{2} O$.
$4 Zn ( s )+10 HNO _{2}( aq ) \rightarrow 4 Zn \left( NO _{2}\right)_{2}( aq )+5 H _{2} O ( l )+ N _{2} O ( g )$
Explain the type of reactions represented by the following equations:
$(i)$ $CuSO _{4}+2 NaOH \longrightarrow Cu ( OH )_{2}+ Na _{2} SO _{4}$
Complete the missing components/variables given as $x$ and $y$ in the following reactions
$(a)$ $Pb \left( NO _{3}\right)_{2}\,(aq)+2 KI ( aq ) \longrightarrow PbI _{2}(x)+2 KNO _{3}( y )$
$(b)$ $Cu ( s )+2 Ag NO _{3}( aq ) \longrightarrow Cu \left( NO _{3}\right)_{2}( aq )+x( s )$
You could have noted that when copper powder is heated in a china dish, the surface of copper powder becomes coated with black colour substance.
$(i)$ Why has this black coloured substance formed?
$(ii)$ What is this black substance?
$(iii)$ Write the chemical equation of the reaction that takes place.
Give differences between the displacement and double displacement reactions.
On adding a drop of barium chloride solution to an aqueous solution of sodium sulphite, white precipitate is obtained.
$(a)$ Write a balanced chemical equation of the reaction involved
$(b)$ What other name can be given to this precipitation reaction ?
$(c)$ On adding dilute hydrochloric acid to the reaction mixture, white precipitate disappears. Why ?