What will be the force constant of the spring system shown in the figure
$\frac{{{K_1}}}{2} + {K_2}$
${\left[ {\frac{1}{{2{K_1}}} + \frac{1}{{{K_2}}}} \right]^{ - 1}}$
$\frac{1}{{2{K_1}}} + \frac{1}{{{K_2}}}$
${\left[ {\frac{2}{{{K_1}}} + \frac{1}{{{K_1}}}} \right]^{ - 1}}$
Two identical springs of spring constant $'2k'$ are attached to a block of mass $m$ and to fixed support (see figure). When the mass is displaced from equilibrium position on either side, it executes simple harmonic motion. The time period of oscillations of this sytem is ...... .
Two bodies $M$ and $N $ of equal masses are suspended from two separate massless springs of force constants $k_1$ and $k_2$ respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude $M$ to that of $N$ is
A block of mass $m$ is attached to two springs of spring constants $k_1$ and $k_2$ as shown in figure. The block is displaced by $x$ towards right and released. The velocity of the block when it is at $x/2$ will be
On a smooth inclined plane, a body of mass $M$ is attached between two springs. The other ends of the springs are fixed to firm supports. If each spring has force constant $K$, the period of oscillation of the body (assuming the springs as massless) is
Define simple pendulum and the length of pendulum.