What will be the force constant of the spring system shown in the figure
$\frac{{{K_1}}}{2} + {K_2}$
${\left[ {\frac{1}{{2{K_1}}} + \frac{1}{{{K_2}}}} \right]^{ - 1}}$
$\frac{1}{{2{K_1}}} + \frac{1}{{{K_2}}}$
${\left[ {\frac{2}{{{K_1}}} + \frac{1}{{{K_1}}}} \right]^{ - 1}}$
Two particles of mass $m$ are constrained to move along two horizontal frictionless rails that make an angle $2\theta $ with respect to each other. They are connected by a spring with spring constant $k$ . The angular frequency of small oscillations for the motion where the two masses always stay parallel to each other (that is the distance between the meeting point of the rails and each particle is equal) is
A mass $m$ is suspended from a spring of force constant $k$ and just touches another identical spring fixed to the floor as shown in the figure. The time period of small oscillations is
A spring executes $SHM$ with mass of $10\,kg$ attached to it. The force constant of spring is $10\,N/m$.If at any instant its velocity is $40\,cm/sec$, the displacement will be .... $m$ (where amplitude is $0.5\,m$)
Two bodies $M$ and $N $ of equal masses are suspended from two separate massless springs of force constants $k_1$ and $k_2$ respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude $M$ to that of $N$ is
In the following questions, match column $-I$ with column $-II$ and choose the correct options