3.Current Electricity
hard

Wheatstone bridge principle is used to measure the specific resistance $\left(S_1\right)$ of given wire, having length $L$, radius $r$. If $X$ is the resistance of wire, then specific resistance is: $S_1=X\left(\frac{\pi r^2}{L}\right)$. If the length of the wire gets doubled then the value of specific resistance will be :

A

 $\frac{S_1}{4}$

B

$2 \mathrm{~S}_1$

C

 $\frac{S_1}{2}$

D

 $S_1$

(JEE MAIN-2024)

Solution

As specific resistance does not depends on dimension of wire so, it will not change.

Standard 12
Physics

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