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Question

Rain is falling vertically downwards.

$\vec{v}_{r / m}=\vec{v}_{r}-\vec{v}_{m}$

$	an 60^{\circ}=\frac{ V _{ r }}{ v _{ m }}=\sqrt{3}$

$v _{

Vedclass · Accepted Answer

$0.73$

Vedclass · Answer

Rain is falling vertically downwards.

$\vec{v}_{r / m}=\vec{v}_{r}-\vec{v}_{m}$

$	an 60^{\circ}=\frac{ V _{ r }}{ v _{ m }}=\sqrt{3}$

$v _{ r }= v _{ m } \sqrt{3}= v \sqrt{3}$

Now, $v _{ m }=(1+ B ) v$

and $	heta=45^{\circ}$

$	an 45=\frac{ v _{ r }}{ v _{ m }}=1$

$v _{ r }= v _{ m }$

$v \sqrt{3}=(1+\beta) v$

$\sqrt{3}=1+\beta$

$\Rightarrow \beta=\sqrt{3}-1=0.73$

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