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2. Electric Potential and Capacitance
easy
When a dielectric material is introduced between the plates of a charges condenser, then electric field between the plates
A
Remain constant
B
Decreases
C
Increases
D
First increases then decreases
Solution
(b) In general electric field between the plates of a charged parallel plate capacitor is given by $E = \frac{\sigma }{{{\varepsilon _0}K}}$
Standard 12
Physics