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2. Electric Potential and Capacitance
easy
When a positive $q$ charge is taken from lower potential to a higher potential point, then its potential energy will
A
Decrease
B
Increases
C
Remain unchanged
D
Become zero
Solution
(b) $\Delta \,P.E. = $ Work done by external agent
$ = ({V_f}q – {V_i}q)$${V_f} > {V_i} \Rightarrow \,\Delta P.E. > 0\,i.e.P.E.$ will increase
Standard 12
Physics
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