Gujarati
2. Electric Potential and Capacitance
easy

When a positive $q$ charge is taken from lower potential to a higher potential point, then its potential energy will

A

Decrease

B

Increases

C

Remain unchanged

D

Become zero

Solution

(b) $\Delta \,P.E. = $ Work done by external agent
$ = ({V_f}q – {V_i}q)$${V_f} > {V_i} \Rightarrow \,\Delta P.E. > 0\,i.e.P.E.$ will increase

Standard 12
Physics

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