When a stress of $10^8\,Nm^{-2}$ is applied to a suspended wire, its length increases by $1 \,mm$. Calculate Young’s modulus of wire.

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$\mathrm{Y}=\frac{\mathrm{F} / \mathrm{A}}{\Delta \mathrm{L} / \mathrm{L}}=\frac{1 \times 10^{8}}{10^{-3}}=10^{11} \mathrm{Nm}^{-2}$

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